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Ramgod #3 Cover A G Host Lee (Mature) (Of 6)

Ramgod #3 Cover A G Host Lee (Mature) (Of 6)

USD $4.99

G-Host Lee is a concept artist and illustrator who creates fantasy and sci-fi character art as well as their contributions to Magic: The Gathering. With all eight RAMGOD teams being mandated by the league to add an additional player to their rosters, the Barracudas hold an open tryout to fill the new spot. Having seen the now viral video of the gutsy NCPD Beat Cop pursuing a perpetrator, they extend an invite to Clint. With other pro athletes also invited to the tryouts, the competition is stiff. Out of his element, and unfamiliar with the new sport, Clint must rely on his instincts and athleticism if he's going to make the cut. But when it comes to RAMGOD, even in tryouts, safety is never guaranteed. RAMGOD feels like Point Break meets Fast & Furious, but in a CyberPunk setting that introduces a brand new super high-octane global sport.

Ramgod #3 Cover A G Host Lee (Mature) (Of 6)

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FAQs on Ramgod #3 Cover A G Host Lee (Mature) (Of 6)

How much does "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)" cost at Beyond Comics - Frederick?

The price of "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)" at Beyond Comics - Frederick is USD $4.99.

Who is the publisher of "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)"?

The publisher of "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)" is Sumerian Comics.

What is the genre of "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)"?

The genre of "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)" is Science Fiction.

What category does "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)" fall under?

"Ramgod #3 Cover A G Host Lee (Mature) (Of 6)" falls under the category of Comics.

Who is the artist and cover artist of "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)"?

The artist of "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)" is Hendry Prasetya. The cover artist is G-Host Lee.

Who is the writer of "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)"?

The writer of "Ramgod #3 Cover A G Host Lee (Mature) (Of 6)" is Morgan Rosenblum.