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Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)

Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)

USD $4.99

ENTER: HERCULES! The son of Zeus sought Thor out - for Toranos' wheel had turned for the Olympians too, and two Gods together might solve such a mystery. The trail took them to a wasteland of snow and ice...to terror and treachery...and to an old foe of Hercules, at the height of her dread power. New series artist JAN BAZALDUA draws the story of the IMMORTAL THOR...and the Night Mother's vengeance. PLUS: PART 5 OF DEADPOOL/WOLVERINE: WEAPON X-TRACTION!

Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)

FAQs on Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)

How much does "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" cost at Geek Geek Nerd Nerd?

The price of "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" at Geek Geek Nerd Nerd is USD $4.99.

What brand is "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" associated with?

"Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" is associated with the Thor brand.

Who is the publisher of "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)"?

The publisher of "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" is Marvel Comics.

What is the genre of "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)"?

The genre of "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" is Superheroes.

What category does "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" fall under?

"Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" falls under the category of Comics.

Who is the artist and cover artist of "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)"?

The artist of "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" is Jan Bazaldua. The cover artist is Alex Ross.

Who is the writer of "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)"?

The writer of "Immortal Thor #13 (Deadpool/Wolverine: Weapon X-Traction)" is Al Ewing.