BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)

BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)

USD $39.99

The epic conclusion to the groundbreaking original series is finally here! Caldwell's master plan is revealed, setting up one final showdown with B. and Diana. At the end of all things, the immortal warrior finds himself faced with a challenge that even he might not endure. And if he does succeed... what will remain of him when there are no more battles left to fight?

BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)

FAQs on BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)

How much does "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" cost at Gutter Pop Comics?

The price of "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" at Gutter Pop Comics is USD $39.99.

What brand is "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" associated with?

"BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" is associated with the BRZRKR brand.

Who is the publisher of "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)"?

The publisher of "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" is Boom! Studios.

What is the genre of "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)"?

The genre of "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" is Action Adventure.

What category does "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" fall under?

"BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" falls under the category of Comics.

Who is the artist and cover artist of "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)"?

The artist of "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" is Matt Kindt. The cover artist is Vincenzo Riccardi.

Who is the writer of "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)"?

The writer of "BRZRKR #12 Boom Store Exclusive Foil Variant Riccardi (Of 12)" is Keanu Reeves.