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Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)

Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)

USD $4.99

Things are heating up around Gotham as Drake struggles to cover the whole city while Dr. Crane and Dr. Quinzel's methods begin to endanger it even more! Can Batman find his way back, or will he be lost to his fear for good?!

Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)

FAQs on Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)

How much does "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" cost at Samurai Comics Glendale?

The price of "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" at Samurai Comics Glendale is USD $4.99.

What brand is "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" associated with?

"Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" is associated with the Batman brand.

Who is the publisher of "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)"?

The publisher of "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" is DC Entertainment.

What is the genre of "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)"?

The genre of "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" is Superheroes.

What category does "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" fall under?

"Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" falls under the category of Comics.

Who is the artist and cover artist of "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)"?

The artist of "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" is Joe Quinones. The cover artist is Jahnoy Lindsay.

Who is the writer of "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)"?

The writer of "Batman '89 Echoes #4 Cover C Jahnoy Lindsay Card Stock Variant (Of 6)" is Sam Hamm.