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The Unbeatable Squirrel Girl #14 (2015)

The Unbeatable Squirrel Girl #14 (2015)

USD $5.00

Squirrel Girl and Ant-Man! It’s the team-up you probably NEVER thought you’d see! Although, if you thought about it for a bit, you probably WOULD expect to see it at some point, since they both hang out with tiny animals and are both super heroes. Honestly, I’m a little surprised it hasn’t happened sooner. Anyway, besides squirrels (adorable) and ants (so tiny, so bitey), this issue also includes wrestling AND philosophy. YES. Finally, am I right?? I am prepared to say this is the #1 BEST COMIC you can buy that features squirrels, ants, wrestling and philosophy!! I am also prepared to say that this is the ONLY comic you can buy that features these four things, but heck, we all have to be the change we want to see in the world, right?

The Unbeatable Squirrel Girl #14 (2015)

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FAQs on The Unbeatable Squirrel Girl #14 (2015)

How much does "The Unbeatable Squirrel Girl #14 (2015)" cost at Samurai Comics Phoenix?

The price of "The Unbeatable Squirrel Girl #14 (2015)" at Samurai Comics Phoenix is USD $5.00.

What brand is "The Unbeatable Squirrel Girl #14 (2015)" associated with?

"The Unbeatable Squirrel Girl #14 (2015)" is associated with the Unbeatable Squirrel Girl brand.

Who is the publisher of "The Unbeatable Squirrel Girl #14 (2015)"?

The publisher of "The Unbeatable Squirrel Girl #14 (2015)" is Marvel Comics.

What is the genre of "The Unbeatable Squirrel Girl #14 (2015)"?

The genre of "The Unbeatable Squirrel Girl #14 (2015)" is Superheroes.

What category does "The Unbeatable Squirrel Girl #14 (2015)" fall under?

"The Unbeatable Squirrel Girl #14 (2015)" falls under the category of Comics.

Who is the artist and cover artist of "The Unbeatable Squirrel Girl #14 (2015)"?

The artist of "The Unbeatable Squirrel Girl #14 (2015)" is Erica Henderson. The cover artist is Erica Henderson.

Who is the writer of "The Unbeatable Squirrel Girl #14 (2015)"?

The writer of "The Unbeatable Squirrel Girl #14 (2015)" is Ryan North.